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Geometric Interpretation of Cramer's Rule

Solve x·v₁ + y·v₂ = b.
Det(A) = 1.0
Det(A₁) = 1.0 (b replaces v₁)
Det(A₂) = 1.0 (b replaces v₂)

x = Det(A₁)/Det(A) = 1.0
y = Det(A₂)/Det(A) = 1.0
v₁ (x, y)
v₂ (x, y)
Target Vector b
Intuition: Since b = x·v₁ + y·v₂, when you replace v₁ with b, the new area is only affected by x·v₁ (because y·v₂ is parallel to v₂, contributing nothing to the area). Therefore, the ratio of the new area to the old area is exactly x.

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